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11m^2-13m=0
a = 11; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·11·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*11}=\frac{0}{22} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*11}=\frac{26}{22} =1+2/11 $
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